Double click on a taskbar icon to launch a new instance of the related program
Scenario: there's a program icon in the taskbar (either pinned or not pinned).
To open a second instance of that program one can now right-click on its icon, wait for the Jump List to open, click on the program "mini"-icon inside it.
A simpler way could be to just double-click the program icon in the taskbar with the left mouse button.
Answer
Me again: actually I just noted that it's also possible to open a new instance of the first ten programs from the left pressing SHIFT+WIN+number. Just for information.
Second, doing it with a double click is possible with the Mouse Button Control Advanced options:
Name: taskbaritem|ldblclick
Value: 4
See help for more info about the Mouse Button Control options.
Thank you RaMMicHael, I just entered this site to write that I found the SHIFT+click method, but you already wrote it. Thank you for the registry information too.
Just a notice: the registry change can't be applied if one's using the portable version of 7+ Taskbar Tweaker, as far as I know.
For the portable version, use the ini file.
e.g.:
[Mouse Button Control]
taskbaritem|ctrl+shift+lclick=3
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Second, doing it with a double click is possible with the Mouse Button Control Advanced options:
Name: taskbaritem|ldblclick
Value: 4
See help for more info about the Mouse Button Control options.